Browse:
1. Tags (more)
-
math area ball zeus advice linear equations hard mathproblem i got some answers but i would like more electrical expected value linear systems binomial random variable criminal procedure graph theory emily dickinson
2. Subject:
- advice-classes
- advice-extracurricular
- algebra
- art
- biology
- calculus
- chemistry
- classes
- clubs
- computer-related
- economics
- english
- extracurricular
- geometry
- history
- languages
- music
- physics
- sports
- student government
- tests (SAT, TOEFL, etc.)
- other - mathematics
- other - sciences
- other - social sciences
- other
3. Subject and grade
Answer this question or recommend an answer

calculate the binding energy for the beryllium-9 nucleus
Add a comment
- By chem116 |
- Category: chemistry |
- Grade level: college and above
- Jul/30/2008 |
- Answers to this question: 1
Answer by: scott8148
First Answer Best Answer
the binding energy of an atomic nucleus can be calculated by finding the "mass defect"
this is the "missing mass" __ so called because the sum of the masses of the protons and neutrons is greater than the mass of the nucleus
this "missing mass" has been converted onto the binding energy of the neucleus
__ and can be calculated using Einstein's famous E=mc^2
the mass of a beryllium-9 atom is 9.012182amu __ 4 protons, 5 neutrons, and 4 electrons
proton mass is 1.007276 amu , neutron mass is 1.008665 amu, and electron mass is 5.486×10−4 amu (amu is atomic mass units; 1.6606x10^-27 kg)
component masses __ 4p + 5n + 9e = 9.077366 amu
mass defect __ 9.077366-9.012182= 0.065184 amu
0.065184 amu x 1.6606x10^-27 kg/1 amu=1.082446x10^-28 Kg
E=mc²=(1.082446x10^-28 Kg)*(3.0x10^8 m/s)²=9.742014x10^-12 J or 60.8048 Mev
this is the "missing mass" __ so called because the sum of the masses of the protons and neutrons is greater than the mass of the nucleus
this "missing mass" has been converted onto the binding energy of the neucleus
__ and can be calculated using Einstein's famous E=mc^2
the mass of a beryllium-9 atom is 9.012182amu __ 4 protons, 5 neutrons, and 4 electrons
proton mass is 1.007276 amu , neutron mass is 1.008665 amu, and electron mass is 5.486×10−4 amu (amu is atomic mass units; 1.6606x10^-27 kg)
component masses __ 4p + 5n + 9e = 9.077366 amu
mass defect __ 9.077366-9.012182= 0.065184 amu
0.065184 amu x 1.6606x10^-27 kg/1 amu=1.082446x10^-28 Kg
E=mc²=(1.082446x10^-28 Kg)*(3.0x10^8 m/s)²=9.742014x10^-12 J or 60.8048 Mev
- Jul/31/2008 |
- Answers by scott8148: 170 |
- Contact |
- Report abuse
I tutor algebra, calculus, chemistry, geometry, physics, other - mathematics, other - sciences.
View my profile
Ask a question
Ask Tutors, fellow students and other clever folks.
Help students
Help students by sharing what you know.
