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How many grams of cadmium are deposited from an (aq) solution of CdSO4
How many grams of cadmium are deposited from an (aq) solution of CdSO4 when an electrical current of 1.15 A flows through the solution for 312 minutes?Add a comment
- By chem116 |
- Category: chemistry |
- Grade level: college and above
- Jul/30/2008 |
- Answers to this question: 1
Answer by: vijaya tiwari
First Answer Best Answer
current ( I ) =1.15 A ,T=312min.=312 x60 sec
quantity of electricity passed=I x T =1.15 x312 x60 C =21528 C
reaction at the cathode
Cd2+ + 2e---->Cd
2F=2x 96500C deposit 1 mol of Cd ie;112g
21528 C will deposit =112x 21528 /2 x 96500
=12.5 g of Cd
quantity of electricity passed=I x T =1.15 x312 x60 C =21528 C
reaction at the cathode
Cd2+ + 2e---->Cd
2F=2x 96500C deposit 1 mol of Cd ie;112g
21528 C will deposit =112x 21528 /2 x 96500
=12.5 g of Cd
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- Jul/30/2008 |
- Answers by vijaya tiwari: 18 |
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